令x=sint,则t=arcsinxdx=costdt√(1-x²)=√(1-sin²t)=cost原式=∫√(1-x²)dx/x²=∫cos²tdt/sin²tdt=∫(1-sin²t)dt/sin²t=∫dt/sin²t-∫dt=-cott-t+c=-√(1-x²)/x-arcsinx+c[由于x=sint, cos²t=1-sin²t=1-x²,cost=√(1-x²),cott=cost/sint=√(1-x²)/x]