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116问答网 > 递等式计算（能巧算的用巧算）（1）1210÷[1815-（450+155）]（2）331+971+129+669（3）2500×9×4（4）8

递等式计算（能巧算的用巧算）（1）1210÷[1815-（450+155）]（2）331+971+129+669（3）2500×9×4（4）8

2025-04-04 15:08:11

推荐回答（1个）

回答1：

（1）1210÷[1815-（450+155）]，
=1210÷[1815-605]，
=1210÷1210，
=1；

（2）331+971+129+669，
=（331+669）+（971+129），
=1000+1100，
=2100；

（3）2500×9×4，
=2500×4×9，
=10000×9，
=90000；

（4）88×101，
=88×（100+1），
=8800×100+86×1，
=8800+88，
=8888；

（5）199×98-98×99，
=（199-99）×98，
=100×98，
=9800．

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