(1)开方得:6x-1=±5,解得:x1=1,x2=- 2 3 ;(2)分解因式得:(3x+1)(x-2)=0,可得3x+1=0或x-2=0,解得:x1=- 1 3 ,x2=2;(3)分解因式得:(x+1)(x+3)=0,可得x+1=0或x+3=0,解得:x1=-1,x2=-3;(4)分解因式得:(2x+1)(2x+1-3)=0,可得2x+1=0或2x+1-3=0,解得:x1=- 1 2 ,x2=1.