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一个两位数，个位上的数比十位上的数小2,这两个数是多少？

2025-03-16 17:18:41

推荐回答（3个）

回答1：

设十位上数字为x，那么个位上数字为x+1，得方程：
10x+x+1=5*(x+x+1)
11x+1=10x+5
x=4
所以这个数的十位上数字为4，个位上数字为4+5，这个两为数是45.

回答2：

图

回答3：

31
42
53
64
75
86
97

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