116问答网 > 已知25℃时，电离常数Ka（HF）=3.6×10-4，溶度积常数Ksp（CaF2）=1.46×10-10．现向1L 0.2mol?L-1HF溶液

已知25℃时，电离常数Ka（HF）=3.6×10-4，溶度积常数Ksp（CaF2）=1.46×10-10．现向1L 0.2mol?L-1HF溶液

2025-03-16 01:47:18
推荐回答（1个）
回答1：

A．电离常数Ka（HF）=3.6×10-4，HF为弱电解质，不能完全电离，25℃时，0.1mol?L-1HF溶液中c（H+）=
3.6×10?4×0.1
mol/L=6×10-3mol/L，pH＞1，故A错误；
B．溶度积只受温度的影响，不随浓度的变化而变化，故B错误；
C．溶液中存在HF?H++F-，CaF2（s）?Ca2+（aq）+2F-（aq），加入CaCl2溶液后，Ca2+浓度增大，平衡向生成沉淀的方向移动，则F-浓度减小，促进HF的电离，c（H+）浓度增大，故C错误；
D．向1L 0.2mol?L-1HF溶液中加入1L 0.2mol?L-1CaCl2溶液，混合后，c（H+）=c（F-）=
3.6×10?4×0.1
mol/L=6×10-3mol/L，c（Ca2+）=0.1mol/L，c2（F-）×c（Ca2+）=3.6×10-5×0.1=3.6×10-6＞1.46×10-10，该体系中有CaF2沉淀产生，故D正确．
故选D．

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