单片机流水灯,为什么每次执行都要比上次少亮一个灯

2025-03-15 17:21:49
推荐回答(2个)
回答1:

因为你用了case语句,每一行都要有break;才行。另外,这个程序可以简化,如下
#include
#include
#define led P0
void delay()
{
unsigned int a=50000;
while(a--);
}
void main()
{
unsigned char i;
while(1){
for(i=0;i<8;i++){
switch(i){
case 0:led=0x01; delay();break;
case 1:led=0x02; delay();break;
case 2:led=0x04; delay();break;
case 3:led=0x08; delay();break;
case 4:led=0x10; delay();break;
case 5:led=0x20; delay();break;
case 6:led=0x40; delay();break;
case 7:led=0x80; delay();break;
}
}
}
}

回答2:

建议这样来控制:

void main() { int i,a; unsigned char x;
  while(1) {
  a=50000; while ( a-- ); x=1;
  for ( i=0,x=1;i<8;i++,x<<=1 ) P0=x;
 }
}

你的程序问题出在每个case分支应当以break语句结尾。

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