如果只是要图2的效果,排序就可以了
select * from table order by name;
如果要查每个相同的名字分别有多少个
select name,count(*) from table group by name;
select id,name,age from tablename where name in (select name from tablename group by(name) having count(*)>1)
select name,id,age from table_name where name in (select name from table_name group by name having count(*)>1) order by name;
select name from table_name group by name having count(*)>1用于列出所有 出现2次或2次以上的名字