如何激活已经运行过的Activity,而不是重新启动新的Activity

2025-04-07 09:09:08
推荐回答(1个)
回答1:

假若Activity A已经打开,A没有finish()就跳转到另一个Activiy,
想再重新打开ActivityA 就应该在Manifest.xml中配置这样一个参数
android:name="com.linxi.activity.Register_Activity"
android:launchMode="singleInstance"
android:configChanges="orientation|keyboardHidden"
android:label="werew" />

原理:

Activity启动模式设置:

".MainActivity" android:launchMode="standard" />

Activity的四种启动模式:

1. standard

模式启动模式,每次激活Activity时都会创建Activity,并放入任务栈中。

2. singleTop

如果在任务的栈顶正好存在该Activity的实例, 就重用该实例,否者就会创建新的实例并放入栈顶(即使栈中已经存在该Activity实例,只要不在栈顶,都会创建实例)。

3. singleTask

如果在栈中已经有该Activity的实例,就重用该实例(会调用实例的onNewIntent())。重用时,会让该实例回到栈顶,因此在它上面的实例将会被移除栈。如果栈中不存在该实例,将会创建新的实例放入栈中。

4. singleInstance

在一个新栈中创建该Activity实例,并让多个应用共享改栈中的该Activity实例。一旦改模式的Activity的实例存在于某个栈中,任何应用再激活改Activity时都会重用该栈中的实例,其效果相当于多个应用程序共享一个应用,不管谁激活该Activity都会进入同一个应用中。

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