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116问答网 > 200的变压器带110kw的电机用50平方的铝线距离是250米电压降是多少

200的变压器带110kw的电机用50平方的铝线距离是250米电压降是多少

2025-03-17 03:06:33

推荐回答（2个）

回答1：

110kw电机的额定电流：
I＝P/1.732/U/cosφ＝110/1.732/0.38/0.8≈209(A)
每根50平方铝线的线阻(铝线阻率为0.0283)：
R＝ρ×L/S＝0.0283×250/50≈0.14(Ω)
线与线(任意2根线)之间的电压降：
U＝2RI＝2×0.14×209≈59(V)

回答2：

变压器太小，电动机太大，估计这个电动机无法启动的！！！

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