6x눀+6x-24,当x为多少是时等于0怎么算

2025-03-15 04:10:56
推荐回答(5个)
回答1:

6x²+6x-24=0
x²+x-4=0
(x+1/2)²=17/4
所以x+1/2=根号17/2或x+1/2= - 根号17/2
所以x=根号17 -1/2 或x= - 根号17 -1/2

回答2:

6x^2+6x-24=0
x^2+x-4=0
(x+1/2)^2 = 17/4
x+1/2 = ±√17/2
x = (-1±√17)/2

回答3:

6x²+6x-24 = 0
x²+x-4 = 0
x = (-1±√17)/2

回答4:

奋发图强 奋发图弓虽

回答5:

分解

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