太阳光与地面的夹角求纬度冬至日

2025-04-06 18:58:38
推荐回答(1个)
回答1:

地理--正午太阳高度角计算方法. 某一地区的正午太阳高度角的大小,决定了该地的太阳辐射量的多少,那么,一个地区的正午太阳高度角是否可计算出来呢? 我们已经知道,地球绕太阳公转,由于地轴的倾斜,地轴与轨道平面始终保持着大概66`34'的夹角,这样,才引起太阳直射点在南北纬23`26’之间往返移动,并决定了太阳可能直射的范围:春,秋分日,太阳直射赤道---即直射点的纬度为0`;冬至日,太阳直射南回归线--即直射点的纬度为 23`26’S;夏至日,太阳直射北回归线--即直射点的纬度为23`26’N.如果某地的纬度已经知道,依据下面的公式就可以计算出此地的正午太阳高度角的大小: H=90`-纬差(纬差是指某地的地理纬度与当日直射点所在纬度之间的差值) 例如:A地的纬度为40`N,求A地夏至日的正午太阳高度. 夏至日太阳直射的纬度为23`26’N,与A地的纬度差=40`-23`26’=16`34’,那么H=90`-16`34’=73`26’. 如果求A地冬至日的正午太阳高度.冬至日太阳直射的纬度为23`26’S,与A地的纬度差=40`+23`26’=63`26’,那么H=90`-63`26’=26`34’.

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