一段电阻两端的电压是4v时,通过它的电流是0.2A,如果在它两端再并联上阻值为r的电阻时,干路中的

2025-04-08 00:41:38
推荐回答(3个)
回答1:

1、原电阻的阻值=4/0.2=20欧.
2、当并联上阻值为r的电阻时,干路中的电流增加了0.4A,因为题中没有提到串连分压之类的话,那增加的电流只能是这个并联电阻通过的电流。
那总阻R总=4/(0.2+0.4)=4/0.6=20/3欧=6.666欧。
又总阻=1/20+1/R=(R+20)/20R的倒数
得20/3=20R/(R+20),2R=20,R=10欧。

回答2:

R=4V/02A=20欧姆

回答3:

总电阻6.7欧姆,R的阻值10欧姆

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