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116问答网 > 相同物质的量浓度的NH4HSO4 与NH4(ALSO4)2溶液中铵根离子浓度大小比较，为什么

相同物质的量浓度的NH4HSO4 与NH4(ALSO4)2溶液中铵根离子浓度大小比较，为什么

2025-04-04 06:28:50

推荐回答（2个）

回答1：

（NH4)2CO3+H2O=可逆=NH3+CO2+H2O
水解都是可逆过程,由于NH3的溶解度很大,生成的NH3在温度不高的情形,不会有很多脱离出溶液体系,而再与CO2反应,这样水解很快达到平衡,这样双水解只能部分进行.但是升温可以大大减小气体的溶解度,这样升温后这个双水解可以基本进行彻底.
NH4HSO4=NH4+ + H++SO42- 完全电离
高中认为HSO4-可以完全电离,
铵根水解NH4+ +H2O=可逆=NH3.H2O +H+
因为其溶液中H+的浓度高,可逆反应向逆向进行,
这样NH4HSO4中的NH4+浓度大于（NH4)2CO3中的.

回答2：

第一个大。hso4电离出氢离子抑制氨根水解。

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