由等比数列得性质可得a1a10=a2a9=…=a5a6，又∵a5a6+a4a7=8，∴a1a10=a2a9=…=a5a6=4，∴log2a1+log2a2+…+log2a10=log2（a1?a2?…a10）=log2（a1a10）5=log245=log2210=10故答案为：10
