1分子谷氨酸彻底氧化净生成多少ATP?

2025-04-07 00:14:35
推荐回答(1个)
回答1:

谷氨酸 + NAD(P)+ + H2O (L-谷氨酸脱氢酶)→ a-酮戊二酸 + NH3 + NAD(P)H a-酮戊二酸 (TCA循环)→草酰乙酸(FADH2+2NADH+GTP) 草酰乙酸+GTP (Mg2+ PEP羧激酶)→PEP+GDP+CO2 PEP+ADP(丙酮酸激酶)→丙酮酸+ATP 丙酮酸 + NAD+ + CoASH(丙酮酸脱氢激酶) → 乙酰CoA + NADH + H+ + CO2 乙酰CoA + 3NAD+ + FAD + GDP + Pi + 2H2O (TCA循环)→2CO2 + CoASH + 3NADH + 3H+ + FADH2 + GTP 另外1GTP=1ATP 所以以下有两种算法:首先共消耗1ATP,生成3ATP、7NADH和2FADH 则净生成为-1+3+2.5×7+1.5×2=22.5ATP 其次共消耗1ATP,生成3ATP、6NADH、2FADH和1NADPH 则净生成:-1+3+2.5×6+1.5×2=20ATP

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