解:∠AFD=∠C+∠D,∠AGB=∠B+∠E,∵∠A+∠AFD+∠AGB=180°,∴∠A+∠B+∠C+∠D+∠E=180°,∵∠A=∠B=∠C=∠D=∠E= 1 5 ×180°=36°.故答案为:36°.