116问答网 > 扶梯与地面夹角30°，向上做匀加速运动，人对地面扶梯的压力是重力的5⼀6。求加速度及摩擦力是人重力的几倍

扶梯与地面夹角30°，向上做匀加速运动，人对地面扶梯的压力是重力的5⼀6。求加速度及摩擦力是人重力的几倍

2025-04-02 05:58:52
推荐回答（1个）
回答1：

向上做匀加速运动，有竖直向上的加速度。人对地面扶梯的压力是重力的5/6。却说明支持力小于重力有向下的加速度。不知什么地方错了。
一般而言。人对地面扶梯的压力是重力的6/5。
若是。则说明加速度的竖直向上分量a1=(6G/5-G)/m=0.2g=2m/s^2
加速度a=a1/sin30=4m/s^2
加速度的水平分量a2=acos30
f=ma2=macos30=2√3m
f/G=2√3m/10m=0.2√3倍

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