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当a=-2,b=1时,计算代数式(a+b)^2-(a^2+b^2)的值

2025-03-31 08:30:14

推荐回答（1个）

回答1：

当a=-2,b=1时,
计算代数式(a+b)^2-(a^2+b^2)的值
=(-2+1)²-(4+1)
=1-5
=-4;

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