已知x的平方-4x+1=0,求x-4分之2(x-1)-x分之x+6的值

拜托了/(ㄒoㄒ)/~~
2025-03-22 07:05:20
推荐回答(1个)
回答1:

x^2-4x+1=0
x^2=4x-1

2(x-1)/(x-4) - (x+6)/x
=(2x^2-2x - x^2-2x+24) /(x^2-4x)
=(x^2-4x+24)/(x^2-4x)
= 1 + 24/(x^2-4x)
=1 + 24/(-1)
=-23