解:41×6/7+1/6×6/7等于( 247/7 )
∵已知需求出41×6/7+1/6×6/7等于多少
A × B + A × C = A × (B + C)
∴41 × 6/7 + 1/6 × 6/7
= 6/7 ×(41 + 1/6)
= 6/7 × ( 246/6 + 1/6)
= 6/7 × 247/6
= 247/7
答:41×6/7+1/6×6/7等于247/7
41×6/7+1/6×6/7等于247/42。
41×6/7+1/6×6/7
=6/7×(41+1/6)
=6/7×247/6
=247/7
=35又2/7
41×6/7+1/6×6/7
=6/7X(41+1/6)
=6/7X247/6
=247/7
=7分之247