sin(负6分之17π)的三角函数值

2025-03-15 15:49:09
推荐回答(3个)
回答1:

sin(-17π/6)=-sin(17π/6)=-sin(3π-π/6)=sin(-π/6)=-sin(π/6)=-1/2

回答2:

sin(负6分之17π)
=sin(4π-6分之17π)
=sin(6分之7π)
=sin(负6分之π)
= -1/2

回答3:

sin(-17π/6)
=sin(-17π/6+2π)
=sin(-5π/6)
=-sin(5π/6)
=-sin(π-5π/6)
=-sin(π/6)
=-1/2