116问答网 > 整式乘法与因式分解

整式乘法与因式分解

2025-03-21 16:18:07
推荐回答（2个）
回答1：

(x-y)^2-2(x-y)*(1/2)+(1/2)^2=0
(x-y-1/2)^2=0
x-y-1/2=0
x-y=1/2

回答2：

(x-y)^2-2(x-y)*(1/2)+(1/2)^2=[(x-y)-1/2]^2=0
(x-y)-1/2=0
x-y=1/2

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