(x^2+x-6)/(x-3)除以(x+3)/(x^2-x-6)
=[(x+3)(x-2)/(x-3)]*[(x-3)(x+2)/(x+3)]
=(x-2)(x+2)
=x^2-4
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谢谢
原式=(X+3)(X-2)/(X-3)*(X-3)(X+2)/(X+3)
=(X-2)/(X+2)。
(x^2+x-6)/(x-3)除以(x+3)/(x^2-x-6)
=(x+3)(x-2)/(x-3)× [(x-3)(x+2)/(x+3)]
=(x-2)(x+2)
=x²-4
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