双极性晶体管的工作原理是什么

很急!!
2025-03-26 21:17:05
推荐回答(2个)
回答1:

他回答的很专业

回答2:

双极性晶体管的三个极,分别由N型跟P型组成发射极(Emitter)、基极 (Base) 和集电极(Collector);晶体管因为有三种极性,所以也有三种的使用方式,分别是发射极接地(又称共射放大、CE组态)、基极接地(又称路最常用的用途应该是属于讯号放大这一方面,其次是阻抗匹配、讯号转换……等,晶体管在电路中是个很重要的组件,许多精密的组件主要都是由晶体管制成的。
三极管的导通 三极管处于放大状态还是开关状态要看给三极管基极加的直流偏置,随这个电流变化,三极管工作状态由截止-线性区-饱和状态变化而变, 如果三极管Ib(直流偏置点)一定时,三极管工作在线性区,此时Ic电流的变化只随着Ib的交流信号变化,Ib继续升高,三极管进入饱和状态,此时三极管的Ic不再变化,三极管将工作在开关状态。
三极管为开关管使用时工作在饱和状态1,用放大状态1表示不是很科学。
请对照三极管手册的Ib;Ic曲线加以参考我的回答来理解三极管的工作状态,三极管be结和ce结导通三极管才能正常工作。
如果三极管没有加直流偏置时,放大电路时输入的交流正弦信号正半周时,基极对发射极而言是正的,由于发射结加的是反向电压,此时没有基极电流和集电极电流,此时集电极电流变化与基极反相,在输入电压的负半周,发射极电位对于基极电位为正的,此时由于发射极加的是正向电压,才有基极和集电极电流通过,此时集电极电流变化与基极同相, 在三极管没有加直流偏置时三极管be结和ce结导通,三极管放大电路将只有半个波输出将产生严重的失真。

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