1,2,4,4,7,6,(),(),俩括号里应该填写什么...这是一年级上的题目[衰] 哎
推荐回答(1个)
1 十五之七*0.375+十五分之八*37.5%
原式=7/15 *0.375+8/15 *0.375
=(7/15+8/15)*0.375
=0.375
2 【(四分之三-二分之一)*五分之四】*40%
原式=[(3/4-1/2)*4/5]*40%
=[(3/4-1/2)*4/5]*2/5
=(3/4*4/5-1/2*4/5)*2/5
=(3/5-2/5)*2/5
=1/5*2/5
=1/25
3 0.86+8.6*9.9
原式=0.86+0.86*99
=0.86*(1+99)
=0.86*100
=86
4 四又五十分之七+0.25+7.86+五又四分之三
原式=4.14+0.25+7.86+5.75
=(4.14+7.86)+(0.25+5.75)
=12+6
=18
5 125%*3.2*7.5
原式=(1.25*8)*(0.4*7.5)
=10*3
=30
6 14.5-3.75-25%
原式=14.5-(3.75+0.25)
=14.5-4
=10.5
方程解下列各题
一个数的百分之二十正好是36,求这个数。
设这个数为x。
x*20%=36
x=36/20%
x=180
一个数比12.8的百分之七十五少0.6,这个数是多少?
设这个数为x。
12.8*75%-x=0.6
9.4-x=0.6
x=10
80比120少百分之几?
(120-80)/80=0.5=50%
一个数的三分之二是40,它的百分之40是多少?
设这个数为x。
x*2/3=40 x=60
60*40%=24
追问:
已追加悬赏15分,拜托能不能帮我把这些题也解答了,如果解答得好了,还会给你分的!
应用题解答
一辆汽车从甲地到乙地 第一小时行了全程的百分之二十五,第二小时行了全程的百分之三十,两小时一共行了220千米,甲乙两地全长多少千米?
一项工程,甲队单独做需要10天完成,乙队单独做需要12天完成,甲的工作效率比乙多百分之几?
两匡菜共重84千克,从甲匡取出百分之二十放入乙匡,再从乙匡取出2千克放入甲匡,两匡重量正好相等。求两匡菜原来各重多少千克?
计算。能简算的要简算
1.3*七又五分之四+7.8*7.7+7.8
四又六分之五+十又八分之七-一又十二分之七
【(1.5+二又三分之二)除以三又四分之三-0.4】除以八又九分之八
(一又六分之一-0.75)除以(一又六分之五+一又三分之一)*二又七分之五
(4-三又十七分之八)*(三又七分之四除以一又十四分之一+三又四分之三)
回答:
一辆汽车从甲地到乙地 第一小时行了全程的百分之二十五,第二小时行了全程的百分之三十,两小时一共行了220千米,甲乙两地全长多少千米?
设甲乙两地全长x千米。
25%x+30%x=220
55%x=220
x=400(千米)
一项工程,甲队单独做需要10天完成,乙队单独做需要12天完成,甲的工作效率比乙多百分之几?
(1/10-1/12)/(1/12)=20%
两匡菜共重84千克,从甲匡取出百分之二十放入乙匡,再从乙匡取出2千克放入甲匡,两匡重量正好相等。求两匡菜原来各重多少千克?
设甲筐重x千克 乙筐就是(84-x)千克
x(1-20%)+2=(84-x)+20%x-2
x=50千克
84-50=34
计算。能简算的要简算
1.3*七又五分之四+7.8*7.7+7.8
=1.3*7.8+7.8*7.7+7.8
=7.8*(1.3+7.7+1)
=7.8*10
=78
四又六分之五+十又八分之七-一又十二分之七
=(4+5/6)+(10+7/8)-(19/12)
=14+(5/6+7/8-19/12)
=13+(20/24+21/24-38/24)
=14+1/8
=14.125
【(1.5+二又三分之二)除以三又四分之三-0.4】除以八又九分之八
=[(3/2+8/3)/(15/4)-2/5]/(80/9)
=[(3/2+8/3)*4/15-2/5]*9/80
=(3/2*4/15+8/3*4/15-2/5)*9/80
=(2/5+32/45-2/5)*9/80
=32/45*9/80
=2/25
=0.08
(一又六分之一-0.75)除以(一又六分之五+一又三分之一)*二又七分之五
=(7/6-3/4)/(11/6+4/3)*19/7
=(14/12-9/12)/(19/6)*19/7
=5/12*6/19*19/7
=5/14
(4-三又十七分之八)*(三又七分之四除以一又十四分之一+三又四分之三)
=(4-3-8/17)*(25/7÷15/14+15/4)
=9/17*(25/7*14/15+15/4)
=9/17*(10/3+15/4)
=9/17*85/12
=15/4
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