孝感市某初中物理实验小组的同学想知道小灯泡的亮暗程度与什么因素有关.于是他们找来额定电流小于是0.6A

2025-03-16 03:05:37
推荐回答(1个)
回答1:

(1)灯泡的额定电压为2.5V,所以电压表的量程为0~3V,且与灯泡并联;电流表0.6A的接线柱与滑动变阻器的任意上方接线柱相连,如下图所示:

(2)由表中数据可知,电压表和电流表的示数逐渐增大,由P=UI可知灯泡的实际功率逐渐增大,
灯的亮度是后一次都比前一次亮,则小灯泡越亮,它的实际功率越大;
(3)灯泡正常发光时的电压为2.5V,由表格可知通过灯泡的电流为0.2A,
灯泡的额定功率P=UI=2.5V×0.2A=0.5W;
(4)灯丝电阻受温度影响较大,灯泡在不同电压下,温度不同,灯丝中电阻不同,计算平均值代表灯丝电阻无意义,小明同学忽略了温度对电阻的影响;
(5)无论怎样移动滑动变阻器,小灯泡均不亮,电流表无示数,而电压表有示数且等于电源电压,说明电压表并联的部分断路,电路中出现该故障的原因是小灯泡断路.
故答案为:
(1)如上图所示;
(2)大;
(3)0.5;
(4)温度;
(5)小灯泡断路(合理即可).

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