高中地理题(自然地理)

2024-11-15 17:29:51
推荐回答(5个)
回答1:

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?pwd=1234

提取码:1234

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回答2:

充分利用太阳能是指热水器与太阳光线夹角为90度,也就是说集热板与地面的夹角和太阳高度角相加是90度。根据公式太阳高度等于90减去两地(太阳直射地与当地)的纬度间隔,我们要求调整幅度要先求出集热板与地面夹角的最大值与最小值,也就是当太阳直射南回归线时和直射北回归线时,当太阳直射南回归线时太阳高度为90度-(23度26分+30度)=36度34分,则集热板与地面的夹角为53度26分,当太阳直射北回归线时太阳高度为90度一(30度-23度26分)=83度26分,则集热板与地面的夹角为6度34分,所以调整幅度为53度26分-6度34分所以答案为C
第二题,太阳在同一时刻位于甲乙上中天时,说明甲乙在同一经线上,而且为太阳直射的经线,由甲的太阳高度角为60度根据第一题公式可得甲的纬度是53度26分,同理乙的纬度是77度26分,所以甲乙两地的纬度间隔为24度,每一度大约为111千米,实际距离为24乘以111千米,比例尺为单位换算正确为D

回答3:

1.因为要尽可能使一年内正午太阳光与集热板保持垂直,即太阳直射角和夹角的和尽量多的接近90°,又由于公式H(太阳高度)=90°-纬度差(纬度差就是该地点纬度与太阳直射点的差),得到拉萨最大太阳高度是(90-(30-23.5))=83.5°,最小是(90-(30-(-23.5)))=36.5°,取中间值(83.5+36.5)/2=60°,那么夹角就是(90-60)=30°。选B
2.6月22日,夏至,太阳直射点23.5°,甲乙都在北半球,(90-(甲地纬度-23.5))=60,甲地纬度就是53.5°N,同理,乙地是77.5°N,相差24个纬度,每隔1°差111KM(参考楼上),(44.4*10^-2)/(10^3*111*24)=1/6000000.额,貌似找不到这个答案。。。那就选C吧

回答4:

第一题选C,我的解释如下:
首先,这不是在问你某一时间太阳能热水器的角度值,而是要求一个调整幅度。不知道你们老师说过没有,正午太阳能热水器与地面的夹角等于当地纬度与太阳直射点纬度的差值。而拉萨位于南北回归线之外,它在6月22日达到正午太阳高度的最大值,12月22日最小。题目所要的实际上就是这两日太阳直射点纬度的差值。夏至日时太阳直射北回归线,冬至日即为南回归线。南北回归线夹角即为双倍黄赤交角,即46度52分,故选择C。

第二题选D,解释如下
先解决经度,因为太阳在同一时刻位于甲乙上中天,所以甲乙地方时相同,处于同一条经线,只是纬度有差值。
再来看纬差。题目上说是6月22日,此日太阳直射北回归线,因为甲乙同处北半球,且甲太阳高度为60度,乙地更小,说明甲乙均在北回归线以北,因而甲乙的太阳高度差即为纬度差(原理跟上题的结论一样,要不知道把甲地和乙地的太阳高度表示出来,减一下就知道了)
而甲乙的太阳高度差为60-36=24度,也就是说甲乙两地纬度相差24度,处于同一条经线上。
根据每隔1个纬度的经线长度相等,且约为111千米,有甲乙两地的球面距离为24*111千米。
而图上甲乙距离为44.4厘米,所以有
该图比例尺=44.4厘米/24*111千米=1/60千米,选择D项。
呵呵,个人意见~

回答5:

第一题选B 要使正午太阳光与集热板保持垂直就是当地的纬度!(数学问题,几何解决,我就不多说了)地二题 两地相差24个纬度,乘以每度111KM 就等于实地距离,再除以图上距离就行了.(自己算,多动手!)

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