硼砂标定盐酸溶液,称取硼砂0.523g,用少量蒸馏水溶解,甲基红指示剂.用25.03mlhcl溶液滴定至终点,求hcl的c

na2b4o7·10h2o+2hcl=4h3bo3+5h2o+2nacl na2b4o7·10h2o摩尔质量等于381.4g/mol
2025-03-31 17:32:43
推荐回答(1个)
回答1:

Na2B4O7.10H2O——2HC1
1 2
0.523/381.4 C*25.03/1000
C=(2*0.523/381.4)/(25.03/1000)=0.1096mol/L